Create an Account Nfomedia Log in  Connect with Facebook
Home Blog

SOCI 3311 Blog

A GROUP WEBLOG FOR SOCI3311 - VIDEO ASSISTED SOCI 3311.

« return

January 31, 2010

Assignment 1 Question#6
I am totally confused. I have reviewed the last two semester blogs but the blog does not help. I guess I am confused about what you are asking and the answer I need to submit. This is what I have been working on and I am not sure if this is correct either.

Stem Plot
0 25788
1 000122356777779
2 0000233559
3 022
4 057
5 235
6 066
7 00
8 0
9 00



Quantitative Frequency Distribution
Af Caf Rf Crf
1-10 8 8 .100 ?
11-20 14 22 .320 ?
21-30 7 29 .160 ?
31-40 2 31 .060 ?
41-50 2 33 .060 ?
51-60 3 36 .090 ?
61-70 4 40 .090 ?
71-80 1 41 .200 ?
81-90 2 43 .040 ?


I am really confused on how to calcalate the rf/crf columns. Do you want both of these charts along with the data summarizes? Help? IS THAT POSSIBLE THE POSITIVE SKEW
Posted by      Venkita R. at 4:31 PM CST
Comments (2)
  Dr. Rebecca Guy  says:
rF = aF/N

crF is a cumulative column -- an accumulation of the rF values (computed just as you would compute caF but using rF instead of aF)
Posted on Sun, 31 Jan 2010 5:15 PM CST by Rebecca G.
  Dr. Rebecca Guy  says:
How can the blog NOT help? The ENTIRE STEM PLOT is posted on a blog entry dated January 27, 2010.
Posted on Sun, 31 Jan 2010 5:17 PM CST by Rebecca G.

HOMEWORK #2 1-1
Can some plese tell me where to find this definiton?

Thanks
Posted by      Jeanae D. at 4:01 PM CST
Comments (2)
  Dr. Rebecca Guy  says:
The variance can be defined as the average of the SQUARED deviations from a distribution's mean.
Posted on Sun, 31 Jan 2010 5:14 PM CST by Rebecca G.
  Dr. Rebecca Guy  says:
Found in UNIT 4.
Posted on Sun, 31 Jan 2010 5:14 PM CST by Rebecca G.

Homework #2 Q 1
4. true
6. false
7. true
10. false

Just wondering if these are right! The questions in the unit kind of confused me when I double checked.

Thanks
Posted by      Jeanae D. at 3:32 PM CST
Comments (1)
  Dr. Rebecca Guy  says:
4 is FALSE.
Posted on Sun, 31 Jan 2010 5:13 PM CST by Rebecca G.

Homework #2 Q 2-6, 2-7
I am kind of confused about these questions. For 2-6 i got square root but the review says it is false. For 2-7 i got Average Deviation. Are these correct???
Posted by      Jeanae D. at 3:14 PM CST
Comments (1)
  Dr. Rebecca Guy  says:
The VARIANCE is the SQUARE of the standard deviation.

The STANDARD DEVIATION is the SQUARE ROOT of the variance.

Any score minus the mean is referred to as a DEVIATION FROM THE MEAN (or a DISTANCE SCORE).
Posted on Sun, 31 Jan 2010 5:12 PM CST by Rebecca G.

January 29, 2010

Assignment 2 Q7:4 and 7:5
Can anyone help me figure these out?
Thank you!
Posted by      Brittany B. at 4:22 PM CST
Comments (2)
  Dr. Rebecca Guy  says:
4. The percent of scores between z = -1.00 and z = +1.00 (i.e. read the area between the two z scores listed and multiply by 100).

5. The percent of scores between z = -2.00 and z = +2.00 (i.e. read the area between the two z scores listed and multiply by 100).
Posted on Fri, 29 Jan 2010 4:59 PM CST by Rebecca G.
  Brittany Bacon  says:
Thank you!
Posted on Sun, 31 Jan 2010 5:30 PM CST by Brittany B.

Assignment 1 Q 7.3 & 7.4
I cannot seem to find the answers to these two true/false questions. Can anyone help please. For Q 7.4 I don't think that exactly half of the data in every distribution is above the distribution's mean.
Posted by      Janelle V. at 2:31 PM CST
Comments (1)
  Laura Boswell  says:
You are correct, 7-4 is False
Posted on Fri, 29 Jan 2010 4:35 PM CST by Laura B.

Assignment 1
Hello Mrs. Guy,

I just wanted to confirm that you have received my Assignment from the journal entry. Can you respond to confirm please. Thank you.

Lydia
Posted by      Lydia K. at 2:12 PM CST
Comments (1)
  Dr. Rebecca Guy  says:
Lydia:

Yes. I see it. I will grade it later this evening or tomorrow morning.
Posted on Fri, 29 Jan 2010 4:56 PM CST by Rebecca G.

January 28, 2010

HW #2 5-2&5-3
Since the unit label follows the numbers, would it be students for both 5-2 & 5-3?
Posted by      Jeanae D. at 10:38 PM CST
Comments (2)
  Dr. Rebecca Guy  says:
It would be 'students' for 5-3. However, for variance, it would be 'students squared.'
Posted on Fri, 29 Jan 2010 6:02 AM CST by Rebecca G.
  Jeanae Doughty  says:
Thank you Dr. Guy!!!
Posted on Sat, 30 Jan 2010 1:19 AM CST by Jeanae D.

HOMEWORK #2 Q7
Also i'm having trouble computing these values. Any suggestions?
Posted by      Jeanae D. at 9:00 PM CST
displaying most recent comments (1 ommitted) | Comments (4)
  Jeanae Doughty  says:
the one i was having trouble with was 7-3 do i just enter 99 for 1st and 107 for 2nd??
Posted on Thu, 28 Jan 2010 10:19 PM CST by Jeanae D.
  Dr. Rebecca Guy  says:
You will need to convert 99 to z form using the above procedure.

Then convert 107 to z form using the above procedure.

Then read the area between these two z scores using the STANDARD NORMAL CURVE calculator.

Now multiply this area times 100 to convert it to a %.
Posted on Fri, 29 Jan 2010 8:40 AM CST by Rebecca G.
  Janelle Valle  says:
If we use the same procedure to convert 99 and 107 to z scores (by subtracting 125 from each and then dividing the number by 10) the z score is negative is that correct?
Posted on Fri, 5 Feb 2010 10:43 PM CST by Janelle V.

HOMEWORK #2 Q 6
I'm having trouble understanding how to put thes values in the calculator. Can anyone help???
Posted by      Jeanae D. at 8:59 PM CST
Comments (3)
  Dr. Rebecca Guy  says:
For 6-1 enter 0 for the 1st z score and -3.05 as the second z score. Press calculate.

Do the same for 6-2, 6-3, 6-7, and 6-8.

For 6-6, enter -2 as 1st z score and 2 as 2nd z score. Now subtract this area from 1.00.

For 6-4, you should enter 1.45 as one of the two z scores. Theoretically, the second z score is - ∞. However, we cannot enter - ∞. Instead we will substitute any value smaller than -4 (as virtually 100% of the area lies between -4 and +4). Hence, you can use -5 or -10 or -100 (your choice). Now your two z scores are -10 (for example as a substitution for - ∞ and 1.45. Do the same for 6-9.

For problems 6-5 and 6-10, substitute +5 or +10 or +100 for + ∞.
Posted on Thu, 28 Jan 2010 9:41 PM CST by Rebecca G.
  Jeanae Doughty  says:
so for 6-6 is the answer .0455?
Posted on Thu, 28 Jan 2010 10:36 PM CST by Jeanae D.
  Dr. Rebecca Guy  says:
Yes. Correct! :)
Posted on Fri, 29 Jan 2010 6:03 AM CST by Rebecca G.

Homework Assignment #2 Question 5
Thank you Dr. Guy,
Is the correct answer 27.6 x 27.6 = 761.7?
Posted by      Felicia F. at 11:50 AM CST
Comments (1)
  Dr. Rebecca Guy  says:
Yes. Correct. :)
Posted on Thu, 28 Jan 2010 1:21 PM CST by Rebecca G.

Homework Assignment #2 Question 5
I calculated the sample variance of the terms to be 748.6. Could someone please help me find the correct answer if this is wrong? Thank you.
Posted by      Felicia F. at 10:38 AM CST
Comments (1)
  Dr. Rebecca Guy  says:
Use the statistical calculator (under menu item 'Statistical Calculators') labeled DESCRIPTIVE STATISTICS.

Enter the 7 values listed with the problem. This is done by entering each value followed by the ENTER key. That is, there should only be one value per line (they should appear as a column).

Now press the button labeled CALCULATE.

You should see that the sample standard deviation equals 27.60. SQUARE this value to obtain the VARIANCE.
Posted on Thu, 28 Jan 2010 11:37 AM CST by Rebecca G.

question about 5-8
i thought that in the stem and leaf the numbers for stem were always in the front and that in 1345 the stem is 5 and the leaf was 134. is this not right please explain
Posted by      Kimberly C. at 10:05 AM CST
Comments (3)
  Felicia Floyd  says:
Leaf =5 and the stem= 134
Posted on Thu, 28 Jan 2010 10:29 AM CST by Felicia F.
  Kimberly Crutcher  says:
Thanks thats what i thought.
Posted on Thu, 28 Jan 2010 10:48 AM CST by Kimberly C.
  Dr. Rebecca Guy  says:
The Leaf is the right most digit (in this case 5). The stem is everything else (in this case 134).
Posted on Thu, 28 Jan 2010 11:33 AM CST by Rebecca G.

January 27, 2010

about entering homework assignments
i think i really messed up when i entered my first homework entry. i couldnt do all of the questions in one i had to keep saving them. please tell me what i did or am doing wrong. this is my first online and i am not to familiar with this.
Posted by      Kimberly C. at 10:05 PM CST
Comments (1)
  Felicia Floyd  says:
If you only do half of an assignment, do not mark it as complete when you upload it to your journal. Always click save when you upload. After you finish the assignmet, click 'edit' to add the remaining part of the assignment and then mark as complete when you have done all of the assignment and uploaded.
Posted on Wed, 27 Jan 2010 10:57 PM CST by Felicia F.

Assignment 1 5:7
I can't seem to figure this one out. I know it is probably really simple but it is not clicking!
Can someone help me!
Posted by      Brittany B. at 8:53 PM CST
Comments (2)
  Dr. Rebecca Guy  says:
Assume a data distribution has values ranging between 5 and 50. If the lower limit of the first class interval is 1 and an interval width of 5 is used, _____ class intervals are needed to create a frequency distribution.

Class Intervals Needed:

1 - 5
6 - 10
11 - 15
16 - 20
21 - 25
26 - 30
31 - 35
36 - 40
41 - 45
46 - 50

10 class intervals are needed.
Posted on Thu, 28 Jan 2010 8:07 AM CST by Rebecca G.
  Brittany Bacon  says:
Thank you Dr. Guy!
Posted on Thu, 28 Jan 2010 12:13 PM CST by Brittany B.

Assignment 1 - Problem 9
Because this is such a small data distribution, we cannot really describe it using SHAPE. Instead, we will look at CENTRAL TENDENCY.

If the mean = median = mode, we would likely conclude that the population from which these scores were taken is symmetrical (or normal).

In our case, we have no mode and the mean is smaller than the median.

For what type of distribution (negatively skewed or positively skewed) is the mean smaller than the median?

Our likely conclusion is that these data were taken from a population that is NEGATIVELY skewed.
Posted by      Rebecca G. at 9:28 AM CST
Comments (0)

Assignment 1 - Problem 6
To SUMMARIZE or DESCRIBE the data, you will need to look at the SHAPE of the data distribution. To do this, you need to mentally rotate the stem plot 90 degrees in a counter clockwise direction.

Notice this plot displays a positively skewed distribution -- with the bulk of scores on the low end of the distribution and fewer scores on the high end of the distribution.

Knowing what the scores represent, can you make a summary statement?
Posted by      Rebecca G. at 8:51 AM CST
Comments (1)
  Janelle Valle  says:
How do you copy the stem and leaf graph into the journal? I can't figure it out.
Posted on Fri, 29 Jan 2010 3:59 PM CST by Janelle V.

January 26, 2010

Question on Assignment #1 question 9
What exactly does it mean describe the distribution of the scores?? Or should I say how do you want us to describe?

Also on question #6 #1 what all do you want us to calculate?

I have got the class intervals and the distribution for each interval...are we suppose to calculate more than this??
Posted by      Brittany H. at 11:54 PM CST
Comments (1)
  Dr. Rebecca Guy  says:
A quantitative frequency distribution should include the following columns:

Class Intervals | Absolute Frequencies | Cumulative Absolute Frequencies | Relative Frequencies | Cumulative Relative Frequencies

Beginning with 1 and using an interval width of 10, we would have the following class intevals:

Class Intervals

1-10
11-20
21-30
31-40
41-50
51-60
61-70
71-80
81-90

Now create the absolute frequencies column by COUNTING the number of raw data values that are located in each class interval:
Intervals aF
1-10 9

When you finish you should have:

Class Intervals | aF | caF | rF | crF
Posted on Wed, 27 Jan 2010 8:46 AM CST by Rebecca G.

Q 5-5
HEY ALL IM HAVING TROUBLE WITH THIS QUESTION... IT SAYS IF THE MIDPOINT OF A CLASS INTERVAL (INTERVAL WIDTH=11) IS 15, THE UPPER LIMIT INTERVAL IS ?? IS THERE A FORMULAR THAT I AM MISSING BECAUSE FOR SOME REASON IT'S JUST NOT CLICKING.. THANKS
Posted by      ERICA R. at 11:04 PM CST
Comments (3)
  Dr. Rebecca Guy  says:
If the midpoint is 15 and there are 11 scores, there must be 5 scores on either side of this midpoint.

_ _ _ _ _ 15 _ _ _ _ _

Can you fill in the scores to find the upper limit?
Posted on Wed, 27 Jan 2010 8:38 AM CST by Rebecca G.
  Laura Boswell  says:
The answer would be 20.
Posted on Wed, 27 Jan 2010 12:16 PM CST by Laura B.
  ERICA ROSS  says:
THANKS SO MUCH I WAS DRAWING A BLANK
Posted on Mon, 1 Feb 2010 12:00 PM CST by ERICA R.

Quiz 1
It says homework doesn't have a solid deadline. Are quizzes the same or do they have to be turned in on time?
Posted by      khalid r. at 9:33 AM CST
Comments (3)
  Thomas Mathis  says:
If you click on quiz one it has the date it was opened, and it says through March 5...so I guess it applies for quizzes as well :-)
Posted on Tue, 26 Jan 2010 10:09 AM CST by Thomas M.
  Dr. Rebecca Guy  says:
It does apply to both but the farther behind you get, the harder it is to catch up. Please try to abide by the dates posted.
Posted on Tue, 26 Jan 2010 11:32 AM CST by Rebecca G.
  melissa wiseman  says:
I had a question regarding the quiz dates. Are all quizes due by FEB 26 or March 5?
Posted on Sat, 6 Feb 2010 5:09 PM CST by melissa w.

January 24, 2010

Practice Quiz
I thought I saw a segment that said practice quiz but I can't seem to find it anymore. If there is one, where would I find it?
Posted by      Janelle V. at 3:22 PM CST
Comments (2)
  Thomas Mathis  says:
There are practice quizzes under each unit in the etext :-)...they are located on the left tab.
Posted on Sun, 24 Jan 2010 3:26 PM CST by Thomas M.
  khalid rosli  says:
under practice quizzes on the left click true or false for one of the quizes/multiple choice for the other
Posted on Tue, 26 Jan 2010 9:31 AM CST by khalid r.

January 23, 2010

HOMEWORK & QUIZ GRADES
How and when will we know our grades once we submit an assignment/quiz?
Posted by      Jeanae D. at 12:56 AM CST
Comments (2)
  Dr. Rebecca Guy  says:
I"m ONLINE several hours a day and I try to grade them ASAP.

If you submit an assignment or quiz in the evening, odds are it will not be graded until the following morning.

If you submit an assignment or quiz during the day, it likely could be graded within the hour.
Posted on Sat, 23 Jan 2010 9:31 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
Once grades are posted, they are visible to you via MY GRADES. Just click on MY GRADES.
Posted on Sat, 23 Jan 2010 9:33 AM CST by Rebecca G.

January 22, 2010

ASSIGNMENT #1 Q 7-2
I am kind of confused about this question. I know that you cannot compute the mean or median at the nominal level of measurement but you can compute the mode. So does that make the answer true or false???
Posted by      Jeanae D. at 10:48 PM CST
Comments (1)
  Dr. Rebecca Guy  says:
I'm assuming the question is something like this:

It is not possible to compute central tendency for nominal level data.

The above statement is FALSE as you can compute the MODE which is 1 measure of central tendency.
Posted on Sat, 23 Jan 2010 9:29 AM CST by Rebecca G.

ASSIGNMENT #1 Q 5.6
I am not sure how to compute the true (or real) lower limit of the class interval 5-15.

Can anyone help?!?!?
Posted by      Jeanae D. at 10:17 PM CST
Comments (1)
  Dr. Rebecca Guy  says:
true or real lower limit = lower limit - .5

true or real upper limit = upper limit + .5
Posted on Sat, 23 Jan 2010 10:46 AM CST by Rebecca G.



 Copyright © 2012 Dr. Rebecca Guy. All rights reserved.
Dr. Rebecca Guy | Site Map