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February 27, 2010

Homework 5-5


Can someone please explain to me how to do this problem? I am having trouble determining how to do this.
Posted by      Tegra T. at 8:20 PM CST
  Kathleen Glavin  says:
Hey Tegra, this is the blog post that Dr. Guy put up last year and it was helpful in explaining this problem. I hope it helps. You are just using the Chi Square Analysis Calculator.

Assignment 5 - Problems 3, 4, & 5

--------------------------------------------------------------------------------


5. This problem requires the use of the Chi Square Calculator. Open the chi Square calculator and enter the number of rows (3) and the number of columns (3). Now enter the table into the calculator and click calculate.

You need to complete the hypothesis testing steps for this problem.

Here is the solution:

H(0): Crime rate and temperature are independent of each other.

H(1): Crime rate and temperature not independent of each other.

α = .05

Chi Square obtained = 29.26

Chi Square critical = 9.49 (use the table of chi square values to find this where df = (rows - 1) X (columns - 1))

Because the calculated value of chi square is GREATER than the critical value of chi square, reject H(0). In other words, crime and temperature are not independent of each other.
Posted on Sat, 27 Feb 2010 10:13 PM CST by Kathleen G.
  Tegra Taylor  says:
Thanks Kathleen
Posted on Mon, 1 Mar 2010 7:05 PM CST by Tegra T.

February 26, 2010

Sorry, but I need help.


I don't get Assignment 5
1.4
when did we ever talk about z score conversion?


also is this okay for number 5?
5.
H(0): The crime rate is independent of outdoor temperature.
H(1): The crime rate is dependent on the outdoor temperature.
X2 obtained = 29.26
alpha level =.05
Df = 4
X2 critical = 9.49
Decision: reject the null, the crime rate is dependent on the outdoor temperature.

it doesn't make sense that temperature can affect crime rate. I might be doing something wrong. Anyone?
Posted by      khalid r. at 8:10 PM CST
  khalid rosli  says:
also, is 2.3. vertical intercept ?
Posted on Fri, 26 Feb 2010 8:12 PM CST by khalid r.
  ERICA ROSS  says:
hey khalid, 1.4 is true, and 2.3 is mean or atleast thats what I got hope this helps
Posted on Fri, 26 Feb 2010 8:27 PM CST by ERICA R.
  Dr. Rebecca Guy  says:
5 is correct.

As for 'z score conversion,' please see Unit 11 -- page 26 and following.
Posted on Fri, 26 Feb 2010 10:09 PM CST by Rebecca G.

HW Assign 4 Question 2:5,2:6,2:7


I do not understand Degrees of Freedom. I have read unit 10 and still can not read the information to understand the following questions. Please help...
Answer 2:6 N-1, 2:7 Population ?
Posted by      Venkita R. at 6:55 AM CST
  Kathleen Glavin  says:
I'm not sure if this will help you, but I will try. For 2-5, when you have two samples, the degrees of freedom WITHIN would be the number of raw values (20 and 25) minus the number of samples or groups (2), so therefore the answer would be (20+25-2)=43. With four samples in 2-6, the degrees of freedom BETWEEN is equal to the number of groups or samples (in this case, 4) minus 1. Therefore the answer to 2-6 is (4-1) or 3.

Degrees of freedom BETWEEN= K-1
Degrees of freedom WITHIN=N-K
(K=number of groups or samples, and N=number of raw values)
For 2-7, the best guess of the population variance is the WITHIN VARIANCE ESTIMATE.

I hope that helps!
Posted on Fri, 26 Feb 2010 7:54 AM CST by Kathleen G.
  Dr. Rebecca Guy  says:
Great job, Kathleen! :)
Posted on Fri, 26 Feb 2010 8:22 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
For more information on degrees of freedom, please see Unit 4.
Posted on Fri, 26 Feb 2010 9:11 AM CST by Rebecca G.

February 25, 2010

ASSIGNMENT 5


Is 2-7 the chi square test?
Posted by      Whitney W. at 3:09 PM CST
  Kathleen Glavin  says:
Yes, you're correct.
Posted on Thu, 25 Feb 2010 5:24 PM CST by Kathleen G.
  Dr. Rebecca Guy  says:
Thanks, Kathleen! :)
Posted on Thu, 25 Feb 2010 7:29 PM CST by Rebecca G.
  Kathleen Glavin  says:
Happy to help :)
Posted on Fri, 26 Feb 2010 7:42 AM CST by Kathleen G.

ASSIGNMENT 5


Can someone please help me with these? I'm having a little trouble with them is:
4-1. is it suppose to say positive correlation instead of high?
4-2. I'm not sure about this one at all?
Posted by      Whitney W. at 2:59 PM CST
  Thomas Mathis  says:
This is from a previous blog post:
4-1. The correlation coefficient is a number between -1.00 and +1.00. A value of 1.09 is out of range.

4-2. The correlation coefficient is 'unitless.' That is, no unit label is attached to a correlation coefficient.
Posted on Thu, 25 Feb 2010 6:31 PM CST by Thomas M.
  Dr. Rebecca Guy  says:
Thanks, Thomas! Perfect! :)
Posted on Thu, 25 Feb 2010 7:28 PM CST by Rebecca G.

February 24, 2010

Assignment #5 Q 1-3, 1-5


Can someone tell me if I have these correct please?
1-3. False
1-5. True
Posted by      Janelle V. at 10:52 PM CST
  Dr. Rebecca Guy  says:
Correct. :)
Posted on Thu, 25 Feb 2010 6:24 AM CST by Rebecca G.
  Janelle Valle  says:
Is 1-4. also True?
Posted on Sat, 27 Feb 2010 12:05 PM CST by Janelle V.

Certain symbols


How do we type in certain symbols such as the symbol for the estimate of the standard deviation of sample mean differences? I'm not sure how to put the subscript of "d" after the "s".
Thanks!
Posted by      Kathleen G. at 7:39 PM CST
displaying most recent comments (4 ommitted) | Comments (7)
  Kathleen Glavin  says:
It's the answer to 2-3 on assignment 4.
Posted on Thu, 25 Feb 2010 9:15 AM CST by Kathleen G.
  Randa Kelley  says:
sd


I cant get this to work
Posted on Tue, 1 Mar 2011 6:49 PM CST by Randa K.
  Randa Kelley  says:
in my journal
Posted on Tue, 1 Mar 2011 6:49 PM CST by Randa K.

February 23, 2010

ASSIGNMENT 5


OK I KNOW IM FULL OF QUESTIONS TONIGHT BUT I CANT AFFORD TO LOSE ANY MORE POINTS..

FOR QUESTIONS 3, MY X VARIABLES WOULD BE THE POWERBOATS REGISTRATION, AND MY Y WOULD BE MANTEE KILLED CORRECT?
THESE ARE MY ANSWERS FOR SOME OF QUESTION 3 IS THIS RIGHT?
3.3) STRONG RELATIONSHIP
3.4) 605.424
3.5) 0.76%

ALSO, IS ANYONE ELSE HAVING PROBLEMS USING THE CORRELATION ANALYSIS CALCULATOR FOR SOME REASON AFTER I PLACE MY DATA IN AND HIT CALCULATE NOTHING HAPPENS! I MAY BE DOING SOMETHING WRONG MOST LIKELY.. THANKS!
Posted by      ERICA R. at 9:54 PM CST
displaying most recent comments (3 ommitted) | Comments (6)
  Laurie Johnson  says:
When I squared .941, I got .8855 so 88.6%. Will that be considered correct?
Posted on Wed, 24 Feb 2010 9:09 AM CST by Laurie J.
  Dr. Rebecca Guy  says:
Yes
Posted on Wed, 24 Feb 2010 2:41 PM CST by Rebecca G.
  Thomas Mathis  says:
Haha, you are right laurie...I did it right, just looked at my calculator wrong :-p
Posted on Wed, 24 Feb 2010 3:20 PM CST by Thomas M.

ASSIGNMENT 5


I JUST WANT TO CHECK MY ANSWERS

1-1 I HAVE TRUE
1-6 I HAVE FALSE
2-10 I HAVE CONTINGENCY

2-9 IM A LITTLE CONFUSED IS IT 20? FOR SOME REASON I CANT SEEM TO GET THIS BUT ONCE SOMEONE ANSWERS IT IM SURE IT WILL BE CLEAR THEN LOL.. THANKS
Posted by      ERICA R. at 9:25 PM CST
  Thomas Mathis  says:
I got all of those except on 2-9. It would be 12 because our formula for degrees of freedom is (r-1) x (c-1)....r=rows, c=columns. So, (4-1) x (5-1)=12. Hope that helps :-)
Posted on Tue, 23 Feb 2010 9:32 PM CST by Thomas M.
  ERICA ROSS  says:
THANKS THOMAS YOU SEEM TO BE VERY GOOD AT THIS MAY I ASK WHAT STUDY METHODS YOU USE BECAUSE WHAT IM DOING JUST ISNT WORKING LOL..
Posted on Tue, 23 Feb 2010 9:49 PM CST by ERICA R.
  Thomas Mathis  says:
I'm just one of those people who learns well from reading lol. I do have to say that sometimes I have to read 1 unit twice to get the concepts down :-s And no problem erica, I love to help out when I can
Posted on Tue, 23 Feb 2010 10:39 PM CST by Thomas M.

HW Assignment 5


Hey Dr. Guy, I wanted to check some of the answers I got on the homework assignment.

1.5 true
1.7 true
1.8 false
1.9 false
1.10 false

Also, for 3.5, do we list our answer as a percent (since it's a proportion) or leave it as the decimal we get by squaring r?

For 4.2, I saw in an earlier blog post the answer, but I don't understand why there is no label attached. The correlation is listed as r=.23 bushels? What am I missing?

Thanks so much!!
Posted by      Laurie J. at 6:06 PM CST
  Dr. Rebecca Guy  says:
1. True/False - CORRECT

3.5. Leave as a %

4.2. You are assessing the degree of relationship between 2 variables -- for example, age and income. Which label would you apply? Age? Income?

No unit label is attached to this measurement.
Posted on Tue, 23 Feb 2010 7:17 PM CST by Rebecca G.

February 21, 2010

Assignment 5 Question # 2-4


Could someone please tell me if the square root of the error variance is also called the standard erro of the estimate? Thanks.
Posted by      Felicia F. at 3:43 PM CST
  Dr. Rebecca Guy  says:
Yes
Posted on Sun, 21 Feb 2010 7:28 PM CST by Rebecca G.

1-2, 1-8,1-9, 2-8.


1-2. True
1-8. True
1-9 True
2-8. Analysis of Variance?

I wasn't sure about 2-8.
Posted by      Tiffany W. at 11:56 AM CST
  Dr. Rebecca Guy  says:
Which ASSIGNMENT?
Posted on Sun, 21 Feb 2010 7:27 PM CST by Rebecca G.
  Dr. Rebecca Guy  says:
Let's assume ASSIGNMENT 4:

1-2. False

2-8. Total Variance Estimate
Posted on Mon, 22 Feb 2010 9:10 AM CST by Rebecca G.

February 20, 2010

Assignment #4


Dr. Guy,
Where do we get our t-critical from? I have no idea where it is coming from except from the table I saw from in the unit....but the df only goes to 25 there. Thanks. :-)
Posted by      Thomas M. at 11:26 PM CST
  Dr. Rebecca Guy  says:
You get t critical from that table. Use the df closest (either over or under) to what you need from the table. For example, if df = 32, then use 30 from the table.

The table is found under the menu link labeled STATISTICAL TABLES. Click OPEN for 'Distribution of t.'

Here is a direct link:

http://www.nfomedia.com/static/nfo/442/resources/t.html
Posted on Sun, 21 Feb 2010 8:46 AM CST by Rebecca G.
  Thomas Mathis  says:
This was really confusing me before....thank you so much! :-)
Posted on Sun, 21 Feb 2010 8:48 AM CST by Thomas M.

Assignment 5 2-2


Goodmorning Dr.Guy for question 2-2 would the answer be perfect relationship correlation.
Posted by      Kimberly C. at 9:52 AM CST
  Dr. Rebecca Guy  says:
Yes. :)
Posted on Sat, 20 Feb 2010 8:18 PM CST by Rebecca G.

February 19, 2010

ASSIGNMENT3, QUEST 1


OK IM SORRY IF THIS IS A DUMB QUESTION BUT CAN SOME ONE PLEASE TELL ME HOW TO PLACE THE SYMBOLS IN OUR JOURNALS? I HAVE BEEN WRITING THEM OUT THANKS
Posted by      ERICA R. at 11:53 AM CST
displaying most recent comments (3 ommitted) | Comments (6)
  Laura Boswell  says:
I'm not sure which symbols you are looking for, buy Dr. Guy posted this in an earlier blog.

Type & s i g m a ; (I've included spaces here to show you the exact string of characters needed BUT NO SPACES when you type it) to get σ. PLEASE NOTE: You MUST include the & and the ;

Type & m u ; (I've included spaces here to show you the exact string of characters needed BUT NO SPACES when you type it) to get μ. PLEASE NOTE: You MUST include the & and the ;

Type & s u m ; (I've included spaces here to show you the exact string of characters needed BUT NO SPACES when you type it) to get ∑. PLEASE NOTE: You MUST include the & and the ;

In other words, the & and ; are part of the string.

& s i g m a ; (no spaces please) = σ

& m u ; (no spaces please) = μ

& s u m ; (no spaces please) = ∑

& a l p h a ; (no spaces please) = α

& n e ; (no spaces please) = ≠

& p l u s m n ; (no spaces please) = ±
Posted on Fri, 19 Feb 2010 2:22 PM CST by Laura B.
  ERICA ROSS  says:
thanks laura!!
Posted on Fri, 19 Feb 2010 2:59 PM CST by ERICA R.
  Laura Boswell  says:
You're welcome. = )
Posted on Fri, 19 Feb 2010 3:45 PM CST by Laura B.

February 18, 2010

Assigment #4 Q. 1-6., 1-10, 2-2, and 2-4.


I was just wondering if these answers are correct:
1-6. False
1-10. True
2-2. samples
2-4. summed
Posted by      Janelle V. at 10:07 PM CST
  Dr. Rebecca Guy  says:
All but 1-6. 1-6 is incorrect.
Posted on Fri, 19 Feb 2010 5:05 AM CST by Rebecca G.
  Laura Boswell  says:
I thought 1-10 was false Dr. Guy.
Posted on Fri, 19 Feb 2010 12:13 PM CST by Laura B.

Assignment 4 Q6


For the table do we just but the df, sum of the square and mean of the square? Or do we have to go in more depth?
Posted by      Brittany B. at 3:54 PM CST
  Dr. Rebecca Guy  says:
Write out the entire ANOVA table.
Posted on Thu, 18 Feb 2010 6:51 PM CST by Rebecca G.

assignment 4- 3,4,5


Hi Dr.Guy after i use the t test raw data calculator and got the calculations but what calculator do i use to get t obtain, this is were im stuck. thanks
Posted by      Kimberly C. at 2:36 PM CST
  Dr. Rebecca Guy  says:
This calculator also gives you t obtained (i.e. the calculated value of t).
Posted on Thu, 18 Feb 2010 3:14 PM CST by Rebecca G.

February 17, 2010

Practice Quic M.C. unit 8


Hi I can't figure these questions out. Can someone please explain them.

1. A random sample of 30 households was selected as part of a study on electricity usage and the number of kilowatt-hours (KWh) was recorded for each household in the sample for the March quarter of 2006. The average usage was found to be 375kWh (s=81 kWh). Assuming that usage is normally distributed, provide an expression for computing a 99% confidence interval for the mean usage in the March quarter of 2006. Correct answer: 375+- 40.73


2. To obtain an estimate of the proportion of ?full time? university students who have a part time job in excess of 20 hours per week, student union staff members decide to interview a random sample of full time students. They want the length of their 95% confidence interval to be no greater than 0.1. What size sample should be taken?

N ≅ 96
N ≅ 384
N ≅ 1000

3The recommended retail price of a brand of designer jeans is $150. The price of the jeans in a sample of 16 retailers is on average $141 with a sample standard deviation of 4. If this is a ?random? sample and the prices can be assumed to be normally distributed, construct a 95% confidence interval for the average sale price.

$141 ± $2.13
$141 ± $1.96
$141 ± $2.58
$141 ± $1.56

(I keep getting 141 +- 1.96 and the answer is 141+- 2.13, what am I doing wrong)

4.What is the smallest sample size required to provide a 95% confidence interval for a mean, if it is important that the interval be no longer than 1cm (i.e. margin of error = .5)? You may assume that the population is normal with a variance of 81cm.

N = 1245
N = 95
N = 34
N = 139

I plug everything into the formulas given in the unit and I am not coming up with any of these answers.
Posted by      Brittany B. at 11:03 PM CST
displaying most recent comments (4 ommitted) | Comments (7)
  Dr. Rebecca Guy  says:
Also remember, when you do NOT know the population standard deviation (σ), use t instead of z.
Posted on Thu, 18 Feb 2010 6:41 AM CST by Rebecca G.
  Brittany Bacon  says:
Thank you!!!
Posted on Thu, 18 Feb 2010 12:34 PM CST by Brittany B.
  Dr. Rebecca Guy  says:
You're very welcome. :)
Posted on Thu, 18 Feb 2010 1:32 PM CST by Rebecca G.

Assignmnt # 4 Question 3,4,5


I just wanna make sure I got these answers right

3.H(0): μ(1) = μ(2)
H(1): μ(1) ≠ μ(2)
α = .05
t critical (df=10) =± 2.228
t obtained = .6632
Fail to reject H(0)

4.H(0): μ(1) = μ(2)
H(1): μ(1) ≠ μ(2)
α = .05
t critical (df=60)= ±2.00
t obtained= -2.45
Reject H(0)

H(0): μ(1) = μ(2)
H(1): μ(1) ≠ μ(2)
α = .05
t critical (df= 118) = ±1.98
t obtained = 4.44
Reject H(O)

5.
Posted by      Brittany H. at 2:02 PM CST
  Brittany Hayes  says:
Number 5
H(0): μ(1) = μ(2)
H(1): μ(1) ≠ μ(2)
α = .05
t critical (df= 118) = ±1.98
t obtained = 4.44
Reject H(O)
Posted on Wed, 17 Feb 2010 2:08 PM CST by Brittany H.
  Dr. Rebecca Guy  says:
Yes. They are correct.
Posted on Wed, 17 Feb 2010 4:08 PM CST by Rebecca G.

Assignment # 4 Question 3


I'm not sure if I did this problem right

if there is two sets of data are you suppose to use the two-tail or one-tail t-test.

This is what I got for number 3

Level of significance =.05
t critical (df=10) =2.228-two tail test or one tail test 1.812)
t-obtained= .6632

is this anywhere close to the right answer?
Posted by      Brittany H. at 12:44 PM CST
  Dr. Rebecca Guy  says:
The number of data sets has nothing to do with one- or two-tailed. Please see Unit 8 for an explanation of one- two-tailed tests.

Use two-tailed here

Yes.

You need to add conclusion (i.e. reject Ho or fail to reject Ho)
Posted on Wed, 17 Feb 2010 12:47 PM CST by Rebecca G.

February 16, 2010

Assignment 4-- # 3 and # 4


Dr. Guy,
I am a little confused on #'s 3 and 4 from Assignment #4. I have searched on the blog, but am unable to find any help. Can you help me out or tell me where to look for this information? Thanks for your help.
Brandy Udashen
Posted by      brandy u. at 5:50 PM CST
displaying most recent comments (1 ommitted) | Comments (4)
  Dr. Rebecca Guy  says:
You need to be reading more than the blog. You should also be reading the eText.
Posted on Wed, 17 Feb 2010 8:41 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
These procedures are discussed in detail in UNIT 9.
Posted on Wed, 17 Feb 2010 9:13 AM CST by Rebecca G.
  brandy udashen  says:
Thank you!
Posted on Wed, 17 Feb 2010 10:08 AM CST by brandy u.

February 15, 2010

HW #4


Hey Dr. Guy,

Are the answers for 1-1, 1-4, & 1-7 all FALSE?
Posted by      Jeanae D. at 6:26 PM CST
  Jeanae Doughty  says:
Also, is 2-7 WITHIN VARIANCE ESTIMATE?
In addition, I am having trouble finding the answers to 2-1 & 2-3. Can you help me with these?
Posted on Mon, 15 Feb 2010 6:39 PM CST by Jeanae D.
  Dr. Rebecca Guy  says:
No. They are not all false.

The one-sample t test is used in place of the one-sample z test when the population standard deviation is not known. TRUE

A t test for independent samples can only be used with two samples of equal size. FALSE

When performing tests involving analysis of variance, you must assume that the population distribution from which samples are drawn is approximately normal. TRUE

2-7. Yes

The mean of the sampling distribution of sample mean differences is equal to 0.

The sampling distribution of sample mean differences has a standard deviation equal to σd. An estimate of this standard deviation is symbolized as sd.
Posted on Mon, 15 Feb 2010 7:24 PM CST by Rebecca G.
  Jeanae Doughty  says:
Thanks Dr. Guy!
Posted on Tue, 16 Feb 2010 12:20 PM CST by Jeanae D.

February 14, 2010

assignment 4


One more question Dr. Guy, for question 1-3 it stated when the degrees of freedom are small, the distribution is somewhat flat and spread out. Now according to the text its stated that when the degree is equal to one that it will be more flat and spread out, not how small the number had to be, so would your statement be false.
Posted by      Kimberly C. at 8:15 PM CST
  Dr. Rebecca Guy  says:
Since the SMALLEST possible value for degrees of Freedom is 1, I would certainly define that as small.
Posted on Mon, 15 Feb 2010 7:53 AM CST by Rebecca G.
  Kimberly Crutcher  says:
Thanks!
Posted on Mon, 15 Feb 2010 8:52 AM CST by Kimberly C.

Assignment #3 Question 9-2


I read the previous blog about this question because you have to convert the mean to inches. When I entered the information into the calculator

N= 26
Population Mean=5.833
Standard Deviation=5

I got the answer 5.83 plus or minus 2.15. Is that correct. I saw on the previous blog that the answer was 5.83 plus or minus 0.18.

If the 5.83 plus or minus .18 is the correct answer could you explain to me how.
Posted by      Brittany H. at 7:16 PM CST
displaying most recent comments (3 ommitted) | Comments (6)
  Brittany Hayes  says:
so for 9-3 you would take 5*12=60in + 4in=64.

so it would be:

standard deviation=6
population mean=64
n=36
z=2.58 which comes to 64 plus or minus 2.58?
Posted on Sun, 14 Feb 2010 8:32 PM CST by Brittany H.
  Dr. Rebecca Guy  says:
Yes. You are correct.
Posted on Mon, 15 Feb 2010 7:52 AM CST by Rebecca G.
  Brittany Hayes  says:
thank you!
Posted on Mon, 15 Feb 2010 10:10 AM CST by Brittany H.

assignment 4


Hi Dr. Guy, i wanted to know if i was on the right track with these questions.

1-8.false
1-9.true

2-5. i got 5, do we subtract 25-20 or 20-25 to get the degree of freedom
2-8. total variance estimate
2-9. between variance estimate
2-10.within variance estimate
Posted by      Kimberly C. at 7:01 PM CST
  Dr. Rebecca Guy  says:
The calculated value of F is never negative. TRUE

The F distribution is an entirely positive distribution. TRUE

The number of Within Degrees of Freedom using samples of sizes 20 and 25 is 20+25-2 or 43.

2-8, 9, 10. Correct
Posted on Sun, 14 Feb 2010 8:00 PM CST by Rebecca G.

Practice M.C. quiz Unit 6 #2


Can anyone please explain how to solve this problem?
The probability is .3 that the mean of a sample of 36 terms from an infinite distribution (μ = 155 and σ = 40) will exceed what number?

The answer is 175.80
Posted by      Janelle V. at 1:27 PM CST
displaying most recent comments (1 ommitted) | Comments (4)
  Janelle Valle  says:
I looked at that answer and I still don't understand how the final answer is coming up because I keep getting 158. something.. And I took the quiz and a question similar to it came up and I didn't know how to do it.
Posted on Sun, 14 Feb 2010 3:12 PM CST by Janelle V.
  Dr. Rebecca Guy  says:
The answer on the Quiz is incorrect -- something I just discovered on Wednesday and I have not had a chance to redo the quiz and reload it.

Here's the process and the CORRECT answer:

The z score for which .3 area is ABOVE and .7 area BELOW is .52

Using the ONE SAMPLE Z, we can SUBSTITUTE as follows and then solve for X:

.52 = (X - 155)/(40/√36)

Now solve for X.
Posted on Sun, 14 Feb 2010 4:52 PM CST by Rebecca G.
  Dr. Rebecca Guy  says:
X = 158.47
Posted on Sun, 14 Feb 2010 4:53 PM CST by Rebecca G.

February 12, 2010

Assignment #3 Question 4


Could someone please explain to me how the z obtained value =3.33?
Posted by      Felicia F. at 11:05 PM CST
  Thomas Mathis  says:
Hey Felicia,
I will try to explain. For this problem we are using the One sample Z calculator. Its simply just plugging in the numbers. Our population mean would equal 100 (μ = 100). Our population s.d. (standard deviation) would be 15 (σ=15). Next, you plug in your sample mean which would be 105 (μX=105). The last thing you would input is your sample size, which in this case is 100 U of M students (N=100). When you plug all of these values into the calculator, you will obtain a z value of 3.33. I hope that helps some :-)
Posted on Fri, 12 Feb 2010 11:16 PM CST by Thomas M.
  Dr. Rebecca Guy  says:
Great answer! :)
Posted on Sat, 13 Feb 2010 8:01 AM CST by Rebecca G.

Assignment #3 Q.7


Is the z obtained value= 10.00? And if so, this would mean that the H(0) is rejected because it varies more than .01 of the z-critical right?
Posted by      Janelle V. at 9:51 PM CST
  Janelle Valle  says:
also, I was having doubts about Q. 2-3. Is the correct answer probability?
Posted on Fri, 12 Feb 2010 9:52 PM CST by Janelle V.
  Dr. Rebecca Guy  says:
z obtained is equal to 10.00 Reject Ho.

Total area under the standard normal curve expressed as a proportion is equal to 1.00.
Posted on Sat, 13 Feb 2010 8:02 AM CST by Rebecca G.

Assignment 3 #9


I want to make sure I have calucated the answers on number 9 correctly. (I'm not sure if I calcuated 9-2 and 9-3 correctly because I wasn't sure how to enter in the mean on both of these since they were in feet and inches, so I may have done them completely wrong??! If I did, could you please help me as to what I enter in the calculator as the mean?) Thank you!
9-2 5.83 ± 0.18
9-3 5.33 ± 2.58
9-4 14.00 ± 1.11
9-5 115.00 ± 5.16
Posted by      Laura B. at 4:22 PM CST
  Dr. Rebecca Guy  says:
9-2 and 9-3. Since the standard deviation is given in inches, you need to convert the mean height to inches.
Posted on Fri, 12 Feb 2010 4:42 PM CST by Rebecca G.
  Laura Boswell  says:
Okay thanks. I was keeping it in feet and changing the inches into a fraction instead of converting it to inches. For instance 5'10 would be 5.833. I figured out how to work them all out now. Thank you very much! FYI: The numbering is off on the Practice Exercise on Unit 8. I kept wondering why my answers weren't coming up correctly. There are 2 number 2 questions.
Posted on Fri, 12 Feb 2010 5:00 PM CST by Laura B.

Assigment 3 questions 3.2, 4,5,6,& 7


Dr. Guy.
I just want to know before I take the quiz if these answers are correct. I want to make sure I do understand how to use the formula properly.

3.2 H(0)μ =42,500 AND H(1)= ≠ 42,500

4. H(0) μ =100
H(1) ≠ 100
α=0.1
z-critical = ± 2.58
z-obtained = 3.33
decision to reject H(0) and accept H(1)

5. H(0) μ = 21
H(1) = ≠ 21
α=0.5
z-critical = ± 1.96
z-obtained= -3.43
Decision to reject H(0) and accept H(1)


6 H(0)μ =13
H(1)= ≠ 13
α =0.05
z-critical = ± 1.96
z-obtained = 2.5
Decision to reject H(0) and accept H(1)

7 H(0) μ = 4
H(1) ≠ 4
α =0.01
z-critical = ± 2.58
z-obtained =1.304
Decision is do not reject H(0) and reject H(1)
Posted by      Keiflyn A. at 1:26 AM CST
  Dr. Rebecca Guy  says:
All are correct but 7. z obtained is incorrect for 7.
Posted on Fri, 12 Feb 2010 8:05 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
α = .01 NOT 0.1

or

α = .05 NOT 0.5
Posted on Wed, 17 Feb 2010 3:52 PM CST by Rebecca G.

February 11, 2010

Practice Quiz question


How do you solve this? Do you need the number 36 or is it just to trick you?

unit 6.
2. The probability is .3 that the mean of a sample of 36 terms from an infinite distribution (μ = 155 and σ = 40) will exceed what number?
Posted by      khalid r. at 8:53 PM CST
  Dr. Rebecca Guy  says:
Actually this problem needs to be moved to Unit 7 as the formula to work it does not appear until unit 7.

If you read ahead, here is what you need to do:

First, find the z score that places .3 area ABOVE it and .7 area BELOW it.

Then use the ONE SAMPLE Z formula and solve for X.
Posted on Fri, 12 Feb 2010 8:07 AM CST by Rebecca G.

Assignment #3 problem 3


can anyone help this may sound stupid but i am having an issue. Are we suppose to logically guess or are we actually calculating something. Thanks
Posted by      Kimberly C. at 7:38 PM CST
  Dr. Rebecca Guy  says:
You are suppose to STATE the hypotheses (Null and Research) using the correct syntax.

Please see blog for this problem.
Posted on Fri, 12 Feb 2010 8:08 AM CST by Rebecca G.

Assignment #3 2-8.


I don't seem to understand this question. Is it asking if the degrees of freedom is N-1. Or does it have something to do with the t value?
Posted by      Janelle V. at 1:47 PM CST
  Dr. Rebecca Guy  says:
N-1 is the answer.
Posted on Thu, 11 Feb 2010 6:36 PM CST by Rebecca G.

HW #3 Q 5, 6, 7


Dr. Guy,

I'm really not understanding how to do these problems. I've read the blogs and the section where it explains it in Unit 7. Can you break it down for me???

Thanks
Posted by      Jeanae D. at 12:48 PM CST
  Dr. Rebecca Guy  says:
Please check the BLOG for earlier semesters.
Posted on Thu, 11 Feb 2010 6:35 PM CST by Rebecca G.
  Dr. Rebecca Guy  says:
Actually, you need to read Unit 8 to understand how to do these problems - not Unit 7.
Posted on Thu, 11 Feb 2010 6:36 PM CST by Rebecca G.

assignment 3, #8


hi Dr. Guy i was just wondering if i was putting these computations in the calculator right. im not sure if these are the right answers they look funny, not like in the chapter.

8-1. 110.00plus or minus 2.24
8-2. 77.00 plus or minus 3.59
8-3. 1.40 plus or minus 4.36
8-4. 72 plus or minus 3.53
8-5. 135.00 plus or minus 2.94

are these right.
Posted by      Kimberly C. at 12:20 PM CST
  Dr. Rebecca Guy  says:
close enough
Posted on Thu, 11 Feb 2010 6:34 PM CST by Rebecca G.

Assignment 3 - 9


On problem 9-2 & 9-3 how exactly to you compute the population mean???
Posted by      Rebecca G. at 7:46 AM CST
  Dr. Rebecca Guy  says:
The mean is given to you as is the standard deviation and N.

To compute this interval, use the STATISTICAL CALCULATOR labeled CONFIDENCE INTERVALS USING Z OR T.

When using the 99% confidence interval (with known standard deviation) always use z = ±2.58.
Posted on Thu, 11 Feb 2010 7:49 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
For an explanation of why z equals this value, please see earlier blog (still in February 2010).
Posted on Thu, 11 Feb 2010 10:33 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
When using the 99% confidence interval (with known POPULATION standard deviation) always use z = ±2.58.
Posted on Thu, 11 Feb 2010 10:35 AM CST by Rebecca G.

Assignment 3 - 10


On #10, where do i find the link to STATISTICAL TABLES to start working out this problem???
Posted by      Rebecca G. at 7:44 AM CST
  Dr. Rebecca Guy  says:
Click on the menu item labeled STATISTICAL TABLES.

Click OPEN for the table labeled 'Distribution of t.'

For this problem, you need to use the t table. If you are unclear as how to use it, please see Unit 9.
Posted on Thu, 11 Feb 2010 7:45 AM CST by Rebecca G.

February 10, 2010

HW #3 Q4


Dr. Guy,

I've read the other blogs on this question but I'm not understanding how you arrived at the answer or how you even began. I tried using the calc but I did'nt know what numbers go in the bottom two slots.
Posted by      Jeanae D. at 10:40 PM CST
  Dr. Rebecca Guy  says:
Assignment 3 - Problem 4

Use the ONE SAMPLE Z CALCULATOR:

μ = 100 (i.e. population mean)
σ = 15 (i.e. population standard deviation)
Sample Mean = 105
N = 100 (i.e. sample size)
Posted on Thu, 11 Feb 2010 7:43 AM CST by Rebecca G.

Homework 3 #2-5


What is the difference between a test statistic and a critical statistic?
Posted by      Neil D. at 7:45 PM CST
  Dr. Rebecca Guy  says:
Please see pages 39 and 40 of Unit 7.
Posted on Thu, 11 Feb 2010 7:40 AM CST by Rebecca G.

HW #3


Hey Dr. Guy I was just wondering if I got the correct answers...
1-1 true
1-2 false
1-3 false
1-5 true
1-6 false
1-7 false

They were kind of worded tricky....

Thanks!!!
Posted by      Jeanae D. at 4:11 PM CST
  Dr. Rebecca Guy  says:
6 is true.

Otherwise, correct.
Posted on Wed, 10 Feb 2010 4:44 PM CST by Rebecca G.

Assignment 2 7


For 7-2, I used .3 as the z score and 0 as the other z score and came up with 11.791%. Is this correct? Also is 7-4 68% and 7-5 95%? I'm a little confused. Thank you!
Posted by      Laura B. at 11:23 AM CST
displaying most recent comments (4 ommitted) | Comments (7)
  Dr. Rebecca Guy  says:
Yes. You're right. :)
Posted on Wed, 10 Feb 2010 11:46 AM CST by Rebecca G.
  Laura Boswell  says:
Thanks!! It really took a while to understand this, but it's starting to make sense now. It's not that hard once you figure out what you're doing!
Posted on Wed, 10 Feb 2010 11:52 AM CST by Laura B.
  Dr. Rebecca Guy  says:
Very True. Just takes time.
Posted on Wed, 10 Feb 2010 11:53 AM CST by Rebecca G.

February 9, 2010

Assigment 3 question 8 & 9 & 5


Hey Dr. Guy I read previous blogs on how to work out questions 8 & 9, but my question is why or how do we get z = 1.96 for 8 and 2.58 for 9??? I'm getting different values for both. They are close the values in the blog, but for example #8 I get Z = 1.65
Another question I have is on #5 I am getting -3.43 for z-obtained and I don't know why. Please directed me in the right direction.
Posted by      Keiflyn A. at 2:14 PM CST
  Dr. Rebecca Guy  says:
When using confidence level and population standard deviation is KNOWN, always use z. Because z is a fixed or static distribution, the curve never changes. Therefore, when confidence level is 95%, z will always be ±1.96.

Likewise, when confidence level is 99%, z will always be ±2.58.

This is because the area BETWEEN ±1.96 = 95% and likewise, the area BEYOND these values is 5%.

Similarly, the area BETWEEN ±2.58 = 99% and the area BEYOND these values is 1%.

You have the correct value for z (problem 5).
Posted on Tue, 9 Feb 2010 2:19 PM CST by Rebecca G.
  Dr. Rebecca Guy  says:
z = 1.65 is a position on the curve where 95% of area falls BELOW that value and 5% falls ABOVE that value.

Hence, z = 1.65 is used for DIRECTIONAL testing (specifically, one-directional hypotheses).
Posted on Tue, 9 Feb 2010 3:39 PM CST by Rebecca G.

February 7, 2010

assignment 3 ques.1-2,1-4,1-8,1-9 and 2-5


Hi just wanted to see if i had the right answers to these questions they were worded a little tricky from the way that they are in the book.
1-2 false ,because if the chances that u may pick up a queen would be 4/52 but once you simplify it u get 1/52. help
1-4 true
1-8 true
1-9 true
1-10 true

2-2. 1
2-5 test statistics
Posted by      Kimberly C. at 6:23 PM CST
  Dr. Rebecca Guy  says:
1-10 is FALSE (If the population standard deviation is KNOWN, we would use z, not t.

2-5. 'critical' statistic
Posted on Sun, 7 Feb 2010 8:16 PM CST by Rebecca G.
  Kimberly Crutcher  says:
Thanks Dr. guy !
Posted on Mon, 8 Feb 2010 2:51 PM CST by Kimberly C.

Assignment #2 7-3.


If you use the equation to turn the numbers into z scores and then find the area does the final answer equal 3.13%?
Posted by      Janelle V. at 12:02 PM CST
  Dr. Rebecca Guy  says:
Yes. :)
Posted on Sun, 7 Feb 2010 8:14 PM CST by Rebecca G.

February 5, 2010

Assignment 2 #6 6-4, 6-5, 6-9 & 6-10


I know it's late but these are the only problems that I don't understand how to compute the answer.

Help please!
Posted by      Renicka D. at 8:45 PM CST
  Dr. Rebecca Guy  says:
Please see BLOG entry dated JANUARY 28, 2010 and labeled HOMEWORK #2 Q6
Posted on Fri, 5 Feb 2010 8:56 PM CST by Rebecca G.
  Renicka Deener  says:
Thanks
Posted on Fri, 5 Feb 2010 9:09 PM CST by Renicka D.

Assignment 2 question 5


Could someone explain to me how to go about doing this question, i think i have an idea but i want to make sure im doing it right, kind of confused. Thanks
Posted by      Kimberly C. at 6:34 PM CST
  Dr. Rebecca Guy  says:
Use the DESCRIPTIVE STATISTICS calculator to compute the standard deviation. Square the standard deviation to get variance.

See earlier BLOG entry on Unit Labels (answer to this part of question in an earlier blog entry).
Posted on Fri, 5 Feb 2010 8:15 PM CST by Rebecca G.

unit 5 practice quiz


On the multiple choice practice quiz..
#5 How many terms are in an approximately normal distribution in which 150 terms have z scores above 1.35?
#7 Similar to above.
I dont understand how to solve these.
Posted by      Maria E. at 3:48 PM CST
  Dr. Rebecca Guy  says:
How many terms in an approximately normal distribution of 150 terms have z scores above 1.05?

(1) Find the AREA ABOVE z = 1.05: AREA = .1469

(2) Now we know:

N = .1469 of 150

or

N = .1469(150)

(3)Solve for N: N = 22


How many terms are in an approximately normal distribution in which 150 terms have z scores above 1.35?

(1)Find the AREA ABOVE z = 1.35: AREA = .0885

(2)Now we know:

.0885N = 150

(3) Solve for N: N = 1695
Posted on Fri, 5 Feb 2010 4:38 PM CST by Rebecca G.
  Maria Etters  says:
Thanks. I kept multiplying by the z score instead of the area.
Posted on Sat, 6 Feb 2010 1:36 PM CST by Maria E.

Assignment 2 question 10


10-1. 65.542%
10-2. 5.48%
10-3. 126.75

Are these correct Dr. guy I used the formulas from the blog posted previously
Posted by      Tiffany W. at 2:49 PM CST
  Dr. Rebecca Guy  says:
Yes. :)
Posted on Fri, 5 Feb 2010 4:27 PM CST by Rebecca G.

Assignment 2 question 1-5,2-9


I believe that 1-5 is true I just wanted to make sure that was correct. Also with 2-9 I got 22.73 or 15.8 is this correct?
Posted by      Tiffany W. at 12:45 PM CST
  Dr. Rebecca Guy  says:
1-5 (Assignment 2) is FALSE. The scores closest to the mean will produce the SMALLEST deviations from the mean and hence, the smallest variance and/or standard deviation.

2-9. Standard deviation = SQRT (250/10) or SQRT(25) = 5
Posted on Fri, 5 Feb 2010 2:11 PM CST by Rebecca G.
  Tiffany Williams  says:
Thanks Dr. Guy
Posted on Fri, 5 Feb 2010 2:14 PM CST by Tiffany W.

February 4, 2010

Assignment 2 Question 3


I have yet to find the answer to this question, and I have read both chapters thoroughly. Am I looking past something? Help please!
Posted by      Brittney F. at 11:09 AM CST
  Dr. Rebecca Guy  says:
See Unit 4 page 10 & page 15 as well as Lively Learning for Unit 4
Posted on Thu, 4 Feb 2010 12:29 PM CST by Rebecca G.
  Brittney Fitzgerald  says:
ok thank you so much
Posted on Thu, 4 Feb 2010 2:21 PM CST by Brittney F.

February 3, 2010

HW #2 Q:2:10


How do you calculate the variance if there is no raw data ∑X2=150 and ∑X=25 for a population of 10 scores
Posted by      Brittany H. at 7:43 PM CST
  Dr. Rebecca Guy  says:
Use Formula 4.5 displayed on page 19 of Unit 4

Square ∑X or 25 * 25 = 625

Now Divide this sum by N or 10: 625/10 = 62.5

Subtract this value from ∑X^2: 150 - 62.5 = 87.5

Now divide this by N: 87.5/10 = 8.75

This is VARIANCE.

If you had been asked for the STANDARD DEVIATION, you would need to take the square root of 8.75.
Posted on Thu, 4 Feb 2010 8:13 AM CST by Rebecca G.

February 2, 2010

Assignment #2 QUESTION 2-10


can someone please explain to me how to get the variance?
Posted by      Brittany H. at 11:33 PM CST
  Dr. Rebecca Guy  says:
Use the calculator labeled DESCRIPTIVE STATISTICS. Enter the raw data values (one per line so you will need to press ENTER after each value).

Click CALCULATE.

The calculator will compute the STANDARD DEVIATION.

Once you have the STANDARD DEVIATION, just SQUARE IT.

VARIANCE = STANDARD DEVIATION X STANDARD DEVIATION
Posted on Wed, 3 Feb 2010 7:20 AM CST by Rebecca G.
  Janelle Valle  says:
The only raw data values I see for this problem are 150 and 25. This gives a sample standard deviation of 88.39, therefore making the variance 7812.79. I don't think I am doing the problem right. Please help.
Posted on Fri, 5 Feb 2010 11:00 PM CST by Janelle V.

Assignment #2 Question 6


Dr. Guy,
When I go to the standard normal curve calculator, I click on it, it opens, and I keep getting a white screen (blank), with a blank gray box on the screen. Can you help me out? I'm trying to complete #6 on Assignment 2. Thanks!
Brandy Udashen
Posted by      brandy u. at 11:07 PM CST
  Dr. Rebecca Guy  says:
You need to install JAVA RUNTIME. Please go to the HOME page of the course web site. Click on the RED button near bottom center of page. Follow the prompts.

You may need to reboot once the install is complete. Then try again.
Posted on Wed, 3 Feb 2010 7:18 AM CST by Rebecca G.

February 1, 2010

Multiple choice practice qz. Unit 4


Has anyone worked this problem from the practice quiz-What is the variance for the following frequency distribution (followed with a data set)?

It says the answer is 3.17. I keep getting 8.17. Help!!!
Posted by      Neil D. at 8:16 PM CST
  Dr. Rebecca Guy  says:
To find the ∑Xs, multiply each age by aF and SUM these products.

To find the ∑Xs SQUARED, multiply each age SQUARED by aF and SUM these products

N = ∑ aF.

Now use the computational formula displayed on page 19 of Unit 4 (listed as Formula 4.6).

In other words, treat this as a sample.
Posted on Tue, 2 Feb 2010 8:29 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
The distribution is actually

16
16
16
17
17
17
17
17
17
17
17
18
18
19
19
19
19
and so on

To find the sum of the Xs squared, you would square each of these values ( for example, 19 squared 4 times) or you can square 19 and multiply the squared value by 4.
Posted on Tue, 2 Feb 2010 8:38 AM CST by Rebecca G.
  Neil Dempsey  says:
Haha! I was having a brain fart!!!!! Didn't even notice that there is an af. Thank you so much Dr. Guy!
Neil
Posted on Tue, 2 Feb 2010 4:33 PM CST by Neil D.

HW #2 Q 4


Hey Dr. Guy,

I was wondering if my explanation was good enough for this question. I answered:
"It cannot be negative because there is no upper limit therefore it cannot go below zero in value."
Posted by      Jeanae D. at 7:32 PM CST
  Dr. Rebecca Guy  says:
Yes. It cannot go below 0 because the deviations from the mean are SQUARED which results in either 0 or positive values.
Posted on Tue, 2 Feb 2010 8:19 AM CST by Rebecca G.

HW #2 Q 2-1 & 2-4


I was just wondering if the correct answers are [2-1] squared and [2-4] variance. Seems like the same definition is listed twice.
Posted by      Jeanae D. at 6:47 PM CST
  Dr. Rebecca Guy  says:
Yes. You are right. :)

Sometimes it is necessary to list 3 and 4 times. :)
Posted on Tue, 2 Feb 2010 8:17 AM CST by Rebecca G.
  Dr. Rebecca Guy  says:
And reword as many ways as possible. :)
Posted on Tue, 2 Feb 2010 8:18 AM CST by Rebecca G.
  Jeanae Doughty  says:
Ok thanks!!!
Posted on Tue, 2 Feb 2010 11:43 PM CST by Jeanae D.




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