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October 14, 2010

Assignment 3 Q2-9 & 2-10


I know it is such an easy question...maybe because it is so late at night but I do not understand what it is asking. Can somebody explain it to me? Thanks.
Posted by      Courtney C. at 2:15 AM CDT
  Dr. Rebecca Guy  says:
Please check past blog entries for both of these questions.
Posted on Thu, 14 Oct 2010 3:25 PM CDT by Rebecca G.

October 7, 2010

Assignment 4


Are 1-8 and 1-8 both true? Someone please help. And what did everyone get for 2-1? Just want to get some feedback before I submit my hw. Thanks
Posted by      Shelby S. at 7:18 PM CDT
  Dr. Rebecca Guy  says:
1-8 is TRUE.

2-1. 0
Posted on Fri, 8 Oct 2010 2:03 AM CDT by Rebecca G.

October 6, 2010

Assignment 4 Question 4


Is question 4 supposed to 'look' the same at question 5? I got t critical (df=10)= .66. is this part correct?
Posted by      Shelby S. at 4:23 PM CDT
  Dr. Rebecca Guy  says:
That is correct for Question 4.

Question 5 should 'look' the same.
Posted on Wed, 6 Oct 2010 6:20 PM CDT by Rebecca G.
  Dr. Rebecca Guy  says:
Please see Blog entry (a few days ago) for Question 5.
Posted on Wed, 6 Oct 2010 6:23 PM CDT by Rebecca G.

Assignment 5, Q 2-8


I'm having trouble finding this answer as well. Can anyone help?
Posted by      Rachel W. at 10:12 AM CDT
  Katherine Lugo  says:
It is the research hypothesis, H(1).
Posted on Wed, 6 Oct 2010 2:58 PM CDT by Katherine L.
  Rachel Wahlig  says:
Thank you!
Posted on Wed, 6 Oct 2010 3:22 PM CDT by Rachel W.

October 3, 2010

homework 5


cannot seem to find 2-4 and 2-5

2-4. estimate of the standard error of the mean????
2-5. 0????
Posted by      Sarah B. at 9:49 AM CDT
  Dr. Rebecca Guy  says:
2-4. the standard error of the estimate
2-5. zero
Posted on Sun, 3 Oct 2010 5:46 PM CDT by Rebecca G.

October 2, 2010

Assignment 4 question 5


This what I got for 5

(5)
H(0): μ(1) = μ(2)
H(1): μ(1) ≠ μ(2)
α = .05
t critical (df=58)= ±2.00
t obtained= -2.45
reject H(0)

What I saw posted on the blog as correct was different. What did everyone else get?
Posted by      Sarah B. at 10:54 PM CDT
  Dr. Rebecca Guy  says:
Correct :)
Posted on Sun, 3 Oct 2010 7:40 AM CDT by Rebecca G.

Assignment 5, Q5


I'm not sure if I did this right.

O E O-E (O-E)^2 ((O-E)^2)/E
12.00 9.59 2.41 .61
8.00 10.53 -2.53 .61
5.00 4.89 .11 .00
35.00 31.83 3.17 .32
41.00 34.95 6.05 1.05
7.00 16.23 -9.23 5.25
4.00 9.59 -5.59 3.26
7.00 10.53 -3.53 1.18
14.00 4.89 9.11 16.99

Chi Sq. = 29.26
Posted by      Rachel W. at 9:15 AM CDT
  Dr. Rebecca Guy  says:
You have the correct value for chi square.
Posted on Sun, 3 Oct 2010 7:41 AM CDT by Rebecca G.

October 1, 2010

Assignment 4


Please can someone solve problem 6 and 9, I am completely stuck.
Thanks
Anty.
Posted by      Anty N. at 3:23 AM CDT
  Dr. Rebecca Guy  says:
6.H0: μ1 = μ2
t= 4.44
DF= 120-2= 118
α=0.05= ±1.980
4.44 is out of the ±1.980 range, so we reject H(0). Alcohol altered performance.
Posted on Fri, 1 Oct 2010 8:28 AM CDT by Rebecca G.
  Dr. Rebecca Guy  says:
9.Ho: μ1 = μ2 = μ3 = μ4
H1: Not all group means are equal
α=.05
F= .30
F Critical (numerator=3 , denominator=12) = 3.49
.30 (F) is not in the rejection region and therefore the null hypothesis is not rejected. The machines have the same average time.
Posted on Fri, 1 Oct 2010 8:30 AM CDT by Rebecca G.
  Anty Ndeeyor  says:
Thank you so much Dr. Guy.
Anty.
Posted on Fri, 1 Oct 2010 7:23 PM CDT by Anty N.




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